Homework Answers
The main difference between them are endocrine glands have no ducts and thereby their secretions are directly poured into the bloodstream (e.g. Thyroid gland, Pituitary gland,pineal gland)
The exocrine glands have a duct and thereby their secretions from the ducts are carried to the target tissue (salivary gland,mammary gland,lacrimal gland
So it can be distinguished by the presrnce or absence of ducts.
#11 6.3.19 A Question Help 0 Let uy = 2 -2, and uz = 0 ....
#11
6.3.19 A Question Help 0 Let uy = 2 -2, and uz = 0 . Note that u, and uz are orthogonal but that uz is not orthogonal to u, oruz. It can be shown that uz is not in the subspace 2 W spanned by U, and up. Use this fact to construct a nonzero vector v in R3 that is orthogonal tou, and uz. A nonzero vector in R3 that is orthogonal tou, and uz is v=
Verify that (u,,uz) is an orthogonal set, and then find the orthogonal projection of y onto...
Verify that (u,,uz) is an orthogonal set, and then find the orthogonal projection of y onto Span (u.uz). 1-17 [3] 2,,= -1 . uz = = To verify that (uy,uz) is an orthogonal set, find u. U. Uyuz = 0 (Simplify your answer.) The projection of y onto Span{u,, 42} is (Simplify your answers.)
Use the Gram-Schmidt process to find an orthonormal basis for the subspace spanned by uz =...
Use the Gram-Schmidt process to find an orthonormal basis for the subspace spanned by uz = (1,1,1,1)", u2 = (-1,4,4, -1)", and uz = (4, -2,2,0)".
Find the solution of the given IVP y" + 3y' + 2y = uz(t); y(0) =...
Find the solution of the given IVP y" + 3y' + 2y = uz(t); y(0) = 0, y'(0) = 1 a. y = et-e-t + uz(t) [] + e-(6+2) +22(6+2) b. y = ef +e-t+uz(t)ſ - e-(6-2) + şe-26-2)] + uz(t) - e-(1-2) 3e=2(-2)] e + C. y = e-t-e-27 d. None of these
Find the solution of the given IVP y" + 3y' + 2y = Uz(t); y(0) =...
Find the solution of the given IVP y" + 3y' + 2y = Uz(t); y(0) = 0, y'(0) = 1 + e-(t+2) e-2(t+2) + e 2 a. y=et-e-t + uz(t) [+ b. y=et +e-+ + uz(t) [ – e-(6-2) + že=2(t-2)] c. y = e-t-e-2t + uz(t) (2) - e-(4-2) + že=2(t-2)] + d. None of these
Need help with this problem. BC 1. Solve the vibrating string problem PDE Uz = 4uzz...
Need help with this problem.
BC 1. Solve the vibrating string problem PDE Uz = 4uzz uz(0,t) = 0 ВС uz(1,t) = 0 IC u(a,0) = cos(372) (3,0) = r 0<x< 1, 0 <t< oo 0<t< 0<t<oo 0<x<1 0<x<1. IC
Write v as a linear combination of ui, uz, and U3, if possible. (If not possible,...
Write v as a linear combination of ui, uz, and U3, if possible. (If not possible, enter IMPOSSIBLE.) v=(4, -22, -9, -10), 41 = (1, -3, 1, 1), u2 = (-1, 3, 2, 3), U3 = (0, -2, -2, -2) U1 + uz + U3
Determine if the following basis vectors u1 = (1, 0, 0), uz = (3, 4, 1),...
Determine if the following basis vectors u1 = (1, 0, 0), uz = (3, 4, 1), uz = (1, 3, 5) are linearly independent?
2 4 Let y = 5 uz = 2 Find the distance from y to the...
2 4 Let y = 5 uz = 2 Find the distance from y to the plane in R spanned by u, and uz. 3 1 2 The distance is (Type an exact answer, using radicals as needed.)
(1 point) Solve the heat problem U4 = Uxx, 0 < x < 1, uz (0,t)...
(1 point) Solve the heat problem U4 = Uxx, 0 < x < 1, uz (0,t) = 0, uz(t,t) = 0 u(x,0) = cos? (x) (THINK) u(x, t) =
#11
6.3.19 A Question Help 0 Let uy = 2 -2, and uz = 0 . Note that u, and uz are orthogonal but that uz is not orthogonal to u, oruz. It can be shown that uz is not in the subspace 2 W spanned by U, and up. Use this fact to construct a nonzero vector v in R3 that is orthogonal tou, and uz. A nonzero vector in R3 that is orthogonal tou, and uz is v=
Verify that (u,,uz) is an orthogonal set, and then find the orthogonal projection of y onto Span (u.uz). 1-17 [3] 2,,= -1 . uz = = To verify that (uy,uz) is an orthogonal set, find u. U. Uyuz = 0 (Simplify your answer.) The projection of y onto Span{u,, 42} is (Simplify your answers.)
Use the Gram-Schmidt process to find an orthonormal basis for the subspace spanned by uz = (1,1,1,1)", u2 = (-1,4,4, -1)", and uz = (4, -2,2,0)".
Find the solution of the given IVP y" + 3y' + 2y = uz(t); y(0) = 0, y'(0) = 1 a. y = et-e-t + uz(t) [] + e-(6+2) +22(6+2) b. y = ef +e-t+uz(t)ſ - e-(6-2) + şe-26-2)] + uz(t) - e-(1-2) 3e=2(-2)] e + C. y = e-t-e-27 d. None of these
Find the solution of the given IVP y" + 3y' + 2y = Uz(t); y(0) = 0, y'(0) = 1 + e-(t+2) e-2(t+2) + e 2 a. y=et-e-t + uz(t) [+ b. y=et +e-+ + uz(t) [ – e-(6-2) + že=2(t-2)] c. y = e-t-e-2t + uz(t) (2) - e-(4-2) + že=2(t-2)] + d. None of these
Need help with this problem.
BC 1. Solve the vibrating string problem PDE Uz = 4uzz uz(0,t) = 0 ВС uz(1,t) = 0 IC u(a,0) = cos(372) (3,0) = r 0<x< 1, 0 <t< oo 0<t< 0<t<oo 0<x<1 0<x<1. IC
Write v as a linear combination of ui, uz, and U3, if possible. (If not possible, enter IMPOSSIBLE.) v=(4, -22, -9, -10), 41 = (1, -3, 1, 1), u2 = (-1, 3, 2, 3), U3 = (0, -2, -2, -2) U1 + uz + U3
Determine if the following basis vectors u1 = (1, 0, 0), uz = (3, 4, 1), uz = (1, 3, 5) are linearly independent?
2 4 Let y = 5 uz = 2 Find the distance from y to the plane in R spanned by u, and uz. 3 1 2 The distance is (Type an exact answer, using radicals as needed.)
(1 point) Solve the heat problem U4 = Uxx, 0 < x < 1, uz (0,t) = 0, uz(t,t) = 0 u(x,0) = cos? (x) (THINK) u(x, t) =
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