Question

6. Consider the regioselectivity observed in these E2 reactions. Note that product A forms when the base (methoxide ion, CH307) removes the proton from the carbon labeled B1, while product B forms when the base removes the proton from the carbon labeled B2. Why is formation of the less highly substituted (less stable) double bond favored in product B? (1 pt) CH3 н Bil В. CH₂ Reaction #1 CH30 product A Bro CH2 Bu/ Reaction #2 CH30 - product B н CH3 o В,

Answer 1

In B El Brelimination reaction, the leaving glaip (Elimination and Ht meest be anti to each other. Orbital overlapping is mole when - H & leaving gf are anti treach other. Bax Main fragment Theater clarity Recth 1: It ofta (H₂ Cocuk 2 HBY 12 By H&BY are ant to each - Part Rect 2 EL .H Br Od M part BD PLZ RATE THIS * H& Br are not anti and hence it take from Less sub carbon n Hydrogen is present sy Ret 13 Anti position from the most sub carbon Red Hydrogen is present Antipastion from Less Selbstituted carbon