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The First National Mortgage Company has noted that 8% of its customers pay their mortgage payments after the due date Upload a file detailing all of the work needed to answer the questions. Assume the data is normally distributed. Given a random sample of 150 customers, calculate the mean of the sample. (1 point) Given a random sample of 150 customers, calculate the standard deviation of the sample. (l point) What is the probability that in a random sample of 150 customers less than 7 will be late on their payments? (2 points) What is the probability that in a random sample of 150 customers at least 10 will be late on their payments? (2 points) a. b. с. d.

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Answer #1

a)

n= 150 p= 0.0800
here mean of distribution=μ=np= 12

b)

and standard deviation σ=sqrt(np(1-p))= 3.3226

c)

for normal distribution z score =(X-μ)/σx
therefore from normal approximation of binomial distribution and continuity correction:

P(less then 7 will be late) :

probability = P(X<6.5) = P(Z<-1.66)= 0.0485

d)

P(at least 10 will be late):

probability = P(X>9.5) = P(Z>-0.75)= 1-P(Z<-0.75)= 1-0.2266= 0.7734
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