Question

Problem 52.7 P-30,000 Ib. P-133.4 KN A vertical 6x8 SAS timber column of Douglas Fir is 10-6" tall and is subjected to a compressive load of 30,000 pounds Calculate the unit stress and the total shortening that occurs under this load. Note: A 6x8 SAS has a dressed (actual) dimension of 5%"x7W- 106 6x8 SAS 3.2m I 150x200 S4S Axially loaded timber column (S I. metric) Axially loaded timber column

Answer 1

"Stress = load/surface area Load = 30,00 0Lb (CGS system) = 133.4 kN (SI system) Area = 5 1/2"" times 7 1/2"" = 41.25 inch^2 (CGS) Area = 266.1285 times 10^minus 4 m^2 (SS) Stress = 133.4 times 10^3 N/266.1285 times 10^minus 4m^2 = 5.01 times 10^6 M/m^2 (SI system) (A) Stress = 30,000 lb/41.15 inch^2 = 727.27 lb/inch^2"