The equilibrium constant is given for one of the reactions below. Determine the value of the...

Question

Question

The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. H2

Answer 1

✔ Recommended Answer

Answer #1

Given reaction is:
H2(g) + Br2(g) <-> 2 HBr(g)
Kc = [HBr]^2 / [H2][Br2]
= 3.8*10^4

The required reaction is:
2 HBr(g) <—> H2(g) + Br2(g)
Kc’ = [H2][Br2] / [HBr]^2
= (1/Kc)
= 1/(3.8*10^4)
= 2.6*10^-5

Answer: 2.6*10^-5

Answer 2

Similar Homework Help Questions

The equilibrium constant is given for one of the reactions below. Determine the value of the...

The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. H2(g) + Br2(g) ⇌ 2 HBr(g) Kc = 3.8 × 104 2 HBr(g) ⇌ H2(g) + Br2(g) Kc = ? 2.6 x 10-5 1.6 × 103 6.9 × 10-10 5.9 × 10
9) The equilibrium constant is given for one of the reactions below. Determine the value of...

9) The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. 104 H2(g) + Br2(8) = 2 HBr(g) 2 HBr(g) = H2(g) + Bra(8) Ke3.8 Ke=? A) 1.9 x 104 B) 5.3 x 10-5 C) 2.6 x 10-5 D) 6.4 x 10-4 E) 1.6 % 103 Answer: C Diff:2 Var: 1 Global: G4 LO: 14.3 Page Ref: 14.3
Question 3 Not yet answered Points out of 2 Flag question The equilibrium constant is given...

Question 3 Not yet answered Points out of 2 Flag question The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. H2(g) + Br2(g) 2 HBr(g) Kc 3.8 x 104 2 HBr(g) H2(g) + Br2(g) Kc = ? Select one: O a. 1.9 x 104 ○ b. 5.3 × 10.5 O c. 2.6x 10-5 d. 6.4 x 10-4 e. 1.6 x 103 O o

The equilibrium constant is given for one of the reactions below. Determine the value of the...

The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant. H2(g) + Br2(g) ↔ 2 HBr(g) Kc = 3.8 × 104 2 HBr(g) ↔ H2(g) + Br2(g) Kc = ?
13. The equilibrium constant is given for two of the reactions below. Determine the value of...

13. The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g) 2B (g) AB2(g) Kc 59 AB2(g) + B(g)AB3 (g) Kc? A(g) + 3B ( g) AB 3 (g) KC-478 A) 3.5 x 10-5 B) 2.8 x 104 C) 8.1 D) 0.12 E) 89
QUESTION 1 What does “ICE” stand for, with respect to chemical reactions? Immigration and Customs Enforcement...

QUESTION 1 What does “ICE” stand for, with respect to chemical reactions? Immigration and Customs Enforcement In Case of Emergency Initial, Change, End Initial, Change, Equilibrium None of the above 1 points QUESTION 2 It is possible to solve for the value of K (the equilibrium constant) when: the equilibrium concentrations of all reactants and products are known. only the initial concentrations are known. the initial concentrations of the reactants and the equilibrium concentrations of one or more products are...

the equilibrium constant is given for two of the reactions below. Determine the value of the...

the equilibrium constant is given for two of the reactions below. Determine the value of the missing 23) - equilibrium constant A(g) +B(g) - AB(g) AB(g) + A(g) - A2B(g) 2 A(g) +B(g) - A2B(g) Ke=0.24 Ke = 3.8 Ke=? A) 0.63 B) 4.0 C) 16 D) 0.91 E) 3.6 24) 24) Determine the value of Kp for the following reaction, at 300K, if the equilibrium concentrations are as follows: (N2leq -1.5M, [H2leq = 1.1 M, (NH3 leq = 0.47...
Question 3 (5 points) The equilibrium constant is given for two of the reactions below. Determine...

Question 3 (5 points) The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g) + 2B(g) = AB2(9) Kc = 59 AB2(g) +B(g) = AB3(9) K = ? A(g) + 3B(g) = AB3(9) Kc = 478 8.1 89 0.12 3.5 105 2.8 104
1) Consider the following reaction at equilibrium: H2(g) + Br2(g) = 2 HBr(g) Kc = 3.8...

1) Consider the following reaction at equilibrium: H2(g) + Br2(g) = 2 HBr(g) Kc = 3.8 x 104 a) Is this reaction reactant-favored or product-favored? (1 point) Answer: b) Based on the given equilibrium reaction, determine the value of the equilibrium constant for the following reaction: Show your work for full credit! (4 points) 2 HBr(g) = H2(g) + Br2(g) Kc = c) Use both the equation and your answer from Part b to answer the problem. In a 1.00...

The value of the equilibrium constant for the reaction 2HBr(g)<....>H2(g)+Br2(g) is Kc=1.26*10^-12 at 500k. A. what...

The value of the equilibrium constant for the reaction 2HBr(g)<....>H2(g)+Br2(g) is Kc=1.26*10^-12 at 500k. A. what would be the value of the equilibrium constant K'c for the related reaction written in the following fashion? 1/2 H2(g)+1/2 Br2(g)<....>HBr(g). B. what will be the corresponding value for Kp, the pressure form of the equilibrium constant? (R=0.08206)