Question

I need the answers to these ten questions. I have attached them below. Please answer all of them. Thank you so much in advance!

If a rod is moving at a velocity equal to 1/2 the speed of light parallel to its length, what will a stationary observer observe about its length? O The length of the rod will become exactly half of its original value. O The length of the rod remains the same. The length of the rod will decrease. O The length of the rod will increase

Answer 1

L = L_0 squareroot 1 - nu^2/c^2 where L_0 rightarrow original length L rightarrow approach length nu = C/2, C rightarrow speed of light therefore L = L_0 squareroot 1 - (C/2)^2/C^2 = L_0 squareroot 1 - C^2/4C^2 = L_0 squareroot 3/4 = L = L_0 squareroot 3/2 implies L < L_0 therefore IIIrd option is correct In step-transformer Number of turns in primary coil is more Than number of turns in secondary I-0 = 3.0A implies I_rms = 0.707 times 3 = 2.1 Amp (IInd option) lambda = 200 nm region = ultraviolet region using magnetic Lorenz Force F = q nu B F alpha nu therefore as speed of proton is twice, So Force experienced by proton, is twice therefore 2: 1 (IIIrd option) N = 30, A = 0.25 m^2, W = 100 rad/s B = 0.04 T therefore sigma_max = NWAB = 30 times 100 times 0.25 times 0.04 = 30 volt (IInd option) F = 4N, nu = 100 m/s of theta = 0 degree