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The standard Gibbs energies of formation for Cu2+ (aq) and Fe3+ (aq) are 65.49 kJ mol-1...
) Use standard Gibbs energies of formation to calculate the standard reaction Gibbs energies at 298 K of the reactions (i) Zn(s)+Cu2+ (aq) → Zn2+ (aq)+Cu(s) (ii) C12H2201(s)+1202(8)-12CO2(g)+11H2O0)
Consider the following reaction at 298 K: 3Cu2+(aq) + 2Al(s) + 3Cu(s) + 2 A13+ (aq) and the standard reduction potential values: Cu2+(aq) + 2e + Cu(3) E° = +0.342 v Al3+ (aq) + 3e + Al(s) E° = -1.662 v No files uploaded (Submit 6.1 and 6.2 as a single file) Q6.1 8 Points Calculate the standard Gibbs energy of reaction (A,G), in kJ/mol. Q6.2 8 Points Calculate the emf (E) when [Cu2+] = 1.0 x 10-2 M and...
the standard Gibbs energy of formation (in kJ-mol-) of the compound at 298 K
Consider the Gibbs energies at 25 'C AGi (kJ mol) Substance Ag (aq) 77.1 CI (aq) -131.2 AgCls) -109.8 Br (aq) -104.0 -96.9 AgBr(s) (a) Calculate AGn for the dissolution of AgC1(s) kJ mol (b) Calculate the solubility-product constant of AgCl. K = (c) Calculate AGxn for the dissolution of AgBr(s). kJ mol (d) Calculate the solubility-product constant of AgBr. K =
When the Cu2+ concentration is 6.58×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.979V. What is the Cr3+ concentration? 3Cu2+(aq) + 2Cr(s)3Cu(s) + 2Cr3+(aq) Answer: M When the Cu2+ concentration is 2.71×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.971V. What is the Cr3+ concentration? 3Cu2+(aq) + 2Cr(s)3Cu(s) + 2Cr3+(aq) Answer: M
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq)2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C∘C under each of the following conditions. Part A: standard conditions Part B: [Fe3+]=[Fe3+]= 2.0×10−3 MM ; [Mg2+]=[Mg2+]= 2.25 M Part C: [Fe3+]=[Fe3+]= 2.25 MM ; [Mg2+]=[Mg2+]= 2.0×10−3 M
Consider the Gibbs energies at 25 ∘C. SubstanceSubstance ΔG∘f (kJ⋅mol−1)ΔGf∘ (kJ·mol−1) Ag+(aq)Ag+(aq) 77.177.1 Cl−(aq)Cl−(aq) −131.2−131.2 AgCl(s)AgCl(s) −109.8−109.8 Br−(aq)Br−(aq) −104.0−104.0 AgBr(s)AgBr(s) −96.9−96.9 (a) Calculate ΔG∘rxn for the dissolution of AgCl(s)AgCl(s). kJ⋅mol−1 (b) Calculate the solubility-product constant of AgCl. K= (c) Calculate ΔG∘rxnΔGrxn∘ for the dissolution of AgBr(s)AgBr(s). kJ⋅mol−1kJ⋅mol−1 (d) Calculate the solubility-product constant of AgBr. K=K=
Consider the balanced redox reaction below. 2Hg(I) + 2 Cu2 + (aq) +2CI-(aq)? Hg2CI2(aq) +2 Cu (s) Standard reduction Potentials are given below. Standard Reduction Potentials Reduction Half Reaction Cu2+ (aq) +2e-? Cu (s) 0.34 27 What is the cell potential, Ecell for the following concentrations at 298 K? Cu2+)-0.02M (CI1-0.3M [Hg2Cl21-0.005M Express your answer in units of Volts. 321
What is the ΔrG for the following reaction (in kJ mol-1) at 298 K? 2 Si (s) + 3 H2 (g) ⇌ Si2H6(g) The conditions for this reaction are: PH2 = 1.83 bar PSi2H6 = 0.96 bar You will also need to use Appendix II in your textbook (containing standard Gibbs energies of formation). ΔGf(Si2H6) = 127.3 kJ/mol ΔGf(H2) = 0 kJ/mol
The standard reaction Gibbs energy for the redox process listed below is -206 kJ mol-1. Calculate the standard cell potential. MnO4-(aq) + NO(g) ⟺ MnO2(s) + NO3-(aq) Given these two half-rxns: MnO4-(aq) + 4 H+(aq) + 3 e-⇔ MnO2(s) + 2 H2O(l) NO(g) + 2 H2O(l) ⇔ NO3-(aq) + 4 H+(aq) + 3 e-