Given:
ΔH = 6.11 KJ/mol
= 6110 J/mol
use:
Q = ΔH * number of mol
= 6110 J/mol * 1 mol
= 6110 J
Given:
Q = 6110.0 J
T= 0.0 oC
= (0.0+273) K
= 273 K
use:
ΔS = Q/T
= 6110 J /273 K
= 22.381 J/K
Answer: 22.4 J/K
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