Question

AI, Ule major organic 2, E1, E2) of each reaction. SNI CH2CH2CH2CH_Br to good bare K OC(CH), - sal whol, prolio (CH3),COH, 82°C Nå SCH СН,ОН, 0°C Cty (Itz (It=CH₂ CH3CH2CH2CH BE E, NE, a Na SCH.CH DMF,0°C EM CHI - NaNO2 so (H ₃ NO₂ + Ina Na withy CH; CH3-C-OTS H2O 22°C ESNIE CH CH,OH 22°C E, SNIE K%C(CH3) (CH3),COH, 82°C SNELE 43° C CHI + CHSH Methyl SNr Na CH.CH SN, CH CH2OH, 78°C W E SNE E₂ H20 22°C SASNIELSE, E2 Na 8CH CH,OH, OC

Answer 1

c=cht H . CH, CH2 c=c_ Product) któc (CH3)3 - (1) CH₃ CH₂ CH₂ CH₂ Br - Hace (CH3)₂ COH, 82°C H н" н 254 75.1. (Zaitsev's product) (Hoffmann (Non-zaitsev's) The obou reaction is Ez elimination reaction. Most of the elimination reactions follow Z aitsev's rule: But in case using bulky base" like kol (CH3)3, we get a higher portion ofirion - Zaitsev's" product. or Não CH3 li) CH3 CH, -CH2-CH2-BY CH₂ H C c =ć" + H₂C,c=(-CH3 CH2OH, Qoy, (Non- Zaitsev's product) H À Boy. zaitsev's predict Nomally Ez reactions Substituted alkene follows Zaitsev's rule ne more will be the major product.

is į Na s CH2 CH3 DMF, 0“c CH3 CH3 to etc H₂H CH₂ CH₂S Рис-не и inversion SN2 hey .CH - H - Nace The obou reaction is SN. reaction with in version & TOC (iv) CH₂ I + NaNO2 - 3 This is the reaction between alkyl halice and Nano Nano 2 is an ionic compound and it splits into nat and no, ious. Noz is ambient nucleophile with - electron pair on both N&o , NO, having excess es on o allow it to act as nucleophile in preference ton CHij I + Nă NOI CH₃ NO₂ + NaI Excess of es on o attacks on electrophilic c of CH3 I ; displaces I- & forons nitromethane (CH ₃ NO2).