(a)
Conditional Sampling distributions of primary food choices in lakes A and B:
Lake | Fish | Invertebrates | Birds & Reptiles | Others |
A | 29/56=0.5179 | 4/56=0.0714 | 9/56=0.1607 | 14/56=0.25 |
B | 12/50=0.24 | 17/50=034 | 12/50=0.24 | 9/50=0.18 |
(b)
H0 | Lake and food source are independent |
H1 | Lake and food source are dependent |
(c)
Degrees of Freedom = (r - 1) X (c - 1)
= (2 - 1) X (4 - 1)
= 3
Mean of
Distribution = Degrees of Freedom = 3
Standard Deviation of
Distribution =
Given:
Calculated value of
= 16.32
So, we get:
(16.32 - 3)/2.4495 = 5.4378
So,
Answer is:
This
- value is extreme because it is
5.4378 standard deviations away from mean
3.
(d)
Given:
p value = 0.001
So,
Correct option:
Reject H0. There is sufficient evidence to conclude that Lake and food source are dependent
For alligators caught in two lakes, the accompanying table shows their primary food choice. The four...
For 226 alligators captured in four different lakes, researchers classified the primary food choice (in volume) found in the alligator's stomach in one of the categories - fish, invertebrate, reptile, bird, or other Use the bar chart to answer the following questions 50- 40- Percentage 888 0-1 Other Fish Bird Rep Invert Primary Food Choice of Alligators a. Is primary food choice categorical or quantitative? Categorical Quantitative b. What is the modal category for primary food source? o Other Reptile...