Question

4.5 Generalise the res sults of Section 4.4 to the case in which the level E is g , times degenerate and the level E, is g, times degenerate, and show that the Einstein coefficients satisfy the relations o ba

4.71] 3c in energ the e 4.4 THE EINSTEIN COEFFICIENTS We shall verify that [4.71] is the correct expression for the rate of spontaneous emission by using the treatment of emission and absorption or radiation gi by Einstein in 1916. Consider an enclosure containing atoms (of a single kind) and radiation in equilibrium at absolute temperature T, and let a and b denote two non-degenerate atomic states, with energy values Ea and E E,> E.. We denote by p(obo) the energy density of the radiation at the angular frequency obs (E, E./h. The number of atoms making the transition from a to b per unit time by absorbing radiation, Nba, is proportional to the total ven In c , such that 168

The Einstein coefficients of atoms in the state a and to the energy density poba). That is [4.72] is called the Einstein coefficient for absorption. Since p = 1/c (see where and the transition rate for absorption (per atom) is Wha, we have from 1 cor On the pond. where in the last step we have used the dipole approximation [4.69] for W ba On the other hand, the number of atoms making the transition b a per unit me, Nab, is the sum of the number of spontaneous transitions per unit time, which is independent of p, and the number of stimulated transitions per unit at e, which is proportional to p. Thus N, is the total number of atoms in the state b, Agb is the Einstein coefficient for spontaneous emission and Bab is the Einstein coefficient for stimulated emission. ation Aab WbA eilibrium we have Na Nab, so that from where 4.70] (4.72] and [4.74] we deduce that mming this photon and pontaneous We also know that at thermal equilibrium the ratio Na/N, is given by [9] Bbap(ba vn where k is Boltzmanns constant. From [4.75] and [4.76] we thus find for p(wba) the expression aba ba Since the atoms are in equilibrium with, the radiation at temperature T, the energy density p(o) is given by the Planck distribution law discussed in Section sing [1.31] together with the fact that ρ(w) dw p(v) dv, with ω 2πν, 71 energy density at the particular angular frequency aba is hwba [4.78] ontaneous given kind) b denote such that he angular tion ngle order for [4.77) and [4.78] to be identical, the three Einstein coeffcients must d 2α transitionWISe for instance the text by Kittl (1958). ave 169 o the tota

4.S nteraction of one-electron atoms with electromagnetic radiation be related by the two equations [4.7%) Bba Bab [4.79b] abTe Bab The relation(47%) expresses the principle of detailed balancing discussed previously. Using [4.73] and [4.79], we verify that WabAab) is indeed given in the dipole approximation by the expression [4.71]. It is a simple matter to generalise the above results to the case in which the energy levels Ea and (or) E, are degenerate. Denoting by ga and gb the degeneracy of these levels, one finds (Problem 4.5) that [47%) becomes [4.80] while the relation [4.7%) remains unchanged.

Solve the 4.5 problm.. The results of section 4.4 are given above

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Answer #1

The only change is in equation 4.76, which becomes for degenerate states

Na gaea e-BEa9a-Bhsba 一3hwba

where for simplicity I have used

eta=rac{1}{k_BT}.

As to why, is

Npropto g(E)e^{-eta E}

is based on the classical statistical mechanics. Think of partition function; the energy E term appears g(E) times.

The equations 4.75 and the modified 4.76 yield,

gbAab

OR

Aab Bab b Bab

Thus,

4.79b remains the same, but 4.79a becomes

JaBba gb Bab

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