Homework Answers
In equilibrium net torque = 0
Fy3*r3 - F1*r1 - F2*r2 = 0
r1= 60 cm = 0.6 m
r2 = 20 cm = 0.2 m
r3 = 10 cm = 0.1 m
Fy3*0.1 - 75*0.2 - 180*0.6 = 0
Fy3 = 1230 N
Fy3 = F3*sintheta
F3 = Fy3/sintheta
F3 = 1230/sin25
F3 = 2910 N
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