Question

WORK THIS PROBLEM OUT ON PAPER AND TURN IT IN BEFORE FRI NOV 22. a) Use the data taken in class for the elastic modulus experiment to complete the table. Show a sample calculation for the calculation of stress, strain, and elastic modulus. m (kg) Al (mm) S(N/m?) e E (N/m?) 2.00 4.00 6.00 8.00 10.0 Determine the average elastic modulus from the values in the table. b) On graph paper, plot Al vs m and determine the slope of the best fit line. Use the slope to calculate the elastic modulus.

Delta L numbers are:

0.275

0.460

0.705

0.965

1.175

Thank You!!!

Length is equal to 96.3 cm

Diameter is equal to 0.745+/-0.002m

Answer 1

Elastic Modulus E = stress= strain S e = E = F = mg diameter = d A = for m 2kg mg (2) x (9.8) x (0.745) 44.963 x Nlm2 S e e. =.275 X 10-3 = 2.856 x 10-4 £96 102 E= 44,963 E = 2.856 x 104 E = 1.574 x 103 x N/m2 Similar calculation can be done for other data (4) x (9.8) 89.926 x N/m (0.745)

e=4 0.460 96.3 103 (10-2 = 4.777 x 10-4 e. E= S 89.926 E = 4.777 x 104 E 1.882 x 103 x N/m2 (6) x (9.8) 134.888 x N/m S X (0.745) e = 10-3 0.705 96.3 10 = 7.321 x 10-4 e. X E= S 134,888 E = 7.321 x 104 E = 1.842 x 105 x N/m2 (8) x (9.8) () x (0.745) 179.851 x N/m2 -42 0.965 e 10-3 X = 10.021 x 10-4 e. 96.3 10 E 179.851 E = 10.021 x 10-4 E = 1.795 x 103 x N/m2 (10) X (9.8) 224.814 x N/m2 S X (0.745) e e. - = 12.201 x 10-4 96.3

E = 224.814 E = 12.201 x 104 E = 1.842 x 105 x N/m2 s (N e mm 4.9G32.56 S74 0,275 2 4777 1.82 83.926 ০.५6 ० OTOS31.8987.32 %42 o,965 179.51l0. o 2|1.795 |-४१২ \.17S 221.9/42.20 Average elastic modulus is 1.5741.882 + 1.842 + 1.795+ 1.842 E = 105 E = 1.79 x 105 x N/m2 Graph of Delta I versus M is plotted below

AL 2 1 15 0 10 m -1+ slope = 0.1186 x 10-3 mg E= 4mg E = X лd AL = -X лd" Slope 4g L =0.1186 x 10-3 ла? Е 4g L E = (nd2)x (0.1186 x 103 (4) x (9.8) x (96.3 x 10-2) E = TX (0.1186 x 10-3)x (0.745) E= 1.82 x 105 x N/m2