Question

5.80 is not the answer i dont kmow why, it shows is wrong any help why??

<Homework 5 on Chapter 16 Problem 16.74 - Enhanced - with Feedback Codeine (C18H2NO3) is a weak organic base. A 5.0 x 10M solution of codeine has a pH of 9.95 Part A You may want to reference (Pages 691 - 693) Section 16.7 while completing this problem. Calculate the value of Kh for this substance. Express your answer using two significant figures. VALO Kb = You have already submitted this answer. Enter a new answer No credit lost. Try again Submit Previous Answers Request Answer Part B Complete previous part(s) Provide Feedback

Answer 1

IPOH = 14-PH _ =14-9.95 = 4.0H [OH 7 - 10-poH - 10-4.05 - 8.9x10-5 Ž (18 H₂1 NO H+ + OH (18 H₂, NO₃ + H₂O Initial 0.005 change -8.98 10-5 - Equilibrium 0.005 - (8.9x105) + 8.9x10-5 +8.9x10-5 8.9x10-5 8.9x10-5 (C18 H 12 NO₃ Ht] [oH] [Cis H12 NO3] (8.9x10-5) [0.oos - (8.9x10-57 1.68 10-6 → Answer = Note : 5.80 is the pkb . They have asked for just kb pkb = -log kq = -log (1.6x 10-6) = 5.8