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Chapter 15, Problem 009 When a .22-caliber rifle is fired, the expanding gas from the burning gunpowder creates a pressure behind the bullet. This pressure causes the force that pushes the bullet through the barrel. Suppose the barrel has a length of 0.611 m and an opening whose radius is 2.75 x 10-3 m. A bullet (mass = 2.6 x 10-3 kg) has a speed of 401 m/s after passing through this barrel. Ignore friction and determine the average pressure of the expanding gas. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work SHOW HINT

Answer 1

(i) Info 8= 2.75 X 103 m s=0.611 m. m= 2.6 x 103 kg - O o = 401 mis using uz = u² + 2as (401)2 = 0² + 2ax (0.611) a = 401x401 Now - 2x0.611 a = 131588.3+ mis? f = ma = 2.6 X103 x 13158837 F = 342.12 N And Pressure - force F Area = π82 = 3-14 x 12.75 X103) A = 2.37 x 105 m² P = 342.12 2.37 X10S P = 1.44 x 107 N/m²] ANSWER