Gravity created an Earth-side bulge in the moon, slowing down its rotation in the past to create the synchronous rotation and keeping the longer lunar axis toward our world. Recent research suggested that the side of the moon facing Earth was determined by how quickly the lunar rotation slowed. Because the moon lost speed slowly, there was about a two-to-one chance that the Man in the Moon would wind up facing Earth rather than keeping a space-bound view.
angular momentum L v
velocity v (1/sqrt(radius))
so, the radius must increase to slow down i.e to decrease the velocity of the planet.
In case of any doubt, please do comment sir.
3. Imagine a moon revolving around a planet. If gravitational effects from the moon slow down...
Imagine a moon revolving around a planet. If gravitational effects from the moon slow down the planet's rotation about its own axis, will the orbital radius of the moon increase or decrease in order to conserve the total angular momentum of the planet-moon system? (This is the case with the orbital radius of the moon)
1. A moon of mass \(m\) orbits around a non-rotating planet of mass \(M\) with orbital angular velocity \(\Omega\). The moon also rotates about its own axis with angular velocity \(\omega\). The axis of rotation of the moon is perpendicular to the plane of the orbit. Let \(I\) be the moment of inertia of the moon about its own axis. You can assume \(m<<M\)so that the center ofmass of the system is at the center of the planet.(a) What is...
The tidal forces between the Earth and the Moon slowed down the Moon's rotation about its own axis until the rotation period became equal to the Moon's orbital period around the Earth as we observe today. The same effect is also slowing down the Earth's rotation about its own axis and increasing the separation \(D\) between the Moon and the Earth at a rate of \(\Delta D / \Delta t=3.8 \mathrm{~cm}\) per year. In this problem, you can ignore the...
Problem 1 Planetary Orbits Consider the two-body problem for a planet-star system. The planet, of mass m, is initially in a circular orbit of radius r and angular speed w about the star, of mass M. (i) What is the gravitational potential energy of the system, U? What is the kinetic energy of the planet, K? What is the total energy of the system, E = K +U? (ii) The star suddenly loses half of its mass, M + M/2....
points A newly discovered planet is in a circular orbit around a distant star with an orbital period of 400 Earth days. The planet also rotates on its axis, making one full rotation every 4.00 Earth days. The radius of the planet is rp = 7.00 × 106 m and the radius of the planet's orbit about the star is r 7.00×1011 m. My Notes Ask Your Tea Determine the ratio of the radial acceleration, due to the rotation of...
Question 7 (0.5 points) What causes the Moon to move about 12° across the sky from one night to the next (at the same time of night, of course)? O Because the Earth is turning on its axis. O Because the Moon is moving in its orbit. The Sun has also moved 15° across the sky and gravitationally pulls the Moon with it. The celestial sphere the Moon is attached to has moved 15°. O It is an optical illusion....
1.) So we know that the planet Jupiter and its big Galilean moons are sometimes termed as a ‘mini-solar system’ because Jupiter is composed of mainly hydrogen and helium like stars and the Galilean moons seem like planets revolving around it. The total angular momentum of a system is contributed by the sum of orbital and rotational angular momenta of the central body and the bodies orbiting around it. Note: For parts a and also b you can go ahead...
Cart mr 6- A planet of mass m and radius r orbits a star at a distance R (between their centres) with an angular velocity Wort = 2 rad/s. The planet also rotates around its own axis with an angular velocity of spin = 10 rad/s. The mass of the star is M-1000m. The moment of Star -R 00 inertia of a solid sphere is I = 2 mr 2- Calculate the total angular momentum L of the planet in...
Today, the Moon’s orbit around Earth has a semi-major axis of a=384,400 km and an orbital period of 27.32166 days. a. The Moon slowly moves outward due to tidal braking of the Earth’s rotation, and at some future date the Moon will have an orbital period of 47 days. Compute the semi-major axis of the Moon’s orbit at this future date (express your answer in kilometers). semi-major axis = 5.5*10^5 km b. Today, the Moon has an angular diameter of...
3) Consider the planet Mercury which has mass 3.34 x1023 kg, radius 2.44x10 m, semimajor axis 5.79x1010 m, and eccentricity .206. a) What is the acceleration due to gravity on the surface of Mercury? b) What is the escape velocity from the surface of Mercury? c) Calculate the force exerted on Mercury by the sun at its perihelion and appihelion. d) What are the perihelion and appihelion velocities of Mercury? e) What is Mercury's angular momentum at these two locations?...