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Need Help? Rat 1 152 P013 Three and of the force on the charge q 5.24 nC at the origin. (Let r12 =0.290 m 6.00 nC 0.100 m -3,00 nC magnitude direction Need Help? Mhy 11-13 part, and you wal not be able to back to the
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Answer #1

Concept:- we find the force on the charge individually due to each of the two charges along coordinate axes and then add them using vectors to find the resultant, ч.co/o.1ať 2- 2 So,aqnituoe -S 3.36x10 9 662 so/ dive ction 180+0=256 , 62***************************************************************************************************
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