Question

GENERAL CHEMISTRY I GROUP STUDY ASSIGNMENT TE The first two problems are to be submitted today. 1. (25PTS) An astronaut 300 km above the surface of the earth records a temperature of 226.8°C Calculate the average speed of molecular Oxygen in m/s and mile/hr under these conditions. The formula for the average speed can be derived from the kinetic theory of gases and it is given by SRT average speed = (molar mass) 2. (25PTS) Data: R=0.0821 L atm/(K mole) 8.314 J/K mole), Atomic mass O-16.00 A reaction that can be used to inflate air bags is 2 NaN(S) -----> 2 Na(s) + 3 N28) In a lab simulation, 15.3 mL of N2(g) were obtained at a pressure of 751 torr and 24.5°C. Assuming there were no side reactions, how many grams of NaN:() reacted? Data: Atomic masses: N = 14.01, Na =22.99 ---PEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE h roup.

Answer 1

Date Page D A verage Speed SRT JT m T = 226.8°C 7 = 226.8 + 273 = 499.8k. _m= malar mass malor moss of maleculer oxygen (O2) = - 32 gm 32 X 103 kgimcel R = 8.314 ant mal-1 Average speed = mis 8x8.314 X 499.8 3.14 X 32 X 16-3 33,242.69 100.48 X10-3 330.83 x 1603 575.2 mis .. Aug Speed: $75.2 mis - 1 mis = 2.237 miles Luv speed = 575.2 X2-237 miles lur 1286.68 miles lur

- V = 15.3 ml = 15.3 X 10 L P = 751 tow : 751 atm [760 ton = 1 atm] 760 - 0.988 atm T= 24.5°C 0.082 1 atm kt mall. = 297.5k R = males of N, ² n PV RT {. pvz nRT3_ no 0.988 atm X 15:38 10 34 L 0.082 L atm hlmal' X 297.5k 0.62 X 10 mals. 3 mals of Nr produced from a 2 mal of NaNa 0.62 X 10? males of Nz produced from 2 x 0.62 Xios - 0.413 x 103 mal of Nana mass of Nang = _ - mals x maler moss 0.413 X 10 X 65.02 26853 X10-3_gm 0-02685_go -