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A thin rod extends from x-o to x= 13.0 cm. It has a cross-sectional area A= 6.00 cm2, and its density increases uniformly in the positive x-direction from 2.50 g/cm3 at one endpoint to 18.5 g/cm3 at the other. (a) The density as a function of distance for the rod is given by p-B+ cx, where B and C are constants. What are the values of B (in g/cm3) and C (in g/cm4)? C1.2319/cm (b) Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows. 13.0 cm (B+ Cx)(6.00 cm2) dx allmaterial all x What is the total mass of the rod (in kg)? 4915x Plug in the found values of B and C into the function in the integral. Find the indefinite integral, then evaluate the difference in the result between the two given limits. Review how to find the integral of polynomial terms. kg
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13 0 2 9. )m= O-919111 kg ->please rate

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