Heat absorbed by the substance = 2717 J
Initial temperature of the substance (Ti) = 21.8 oC
Final temperature of the substance (Tf) = 161.4 oC
Temperature difference, = (Tf - Ti) = (161.4 oC - 21.8 oC) = 139.6 oC
Mass of the substance (m) = 31.29 g
Let us say that the specific heat capacity of the substance = s
Now, heat energy absorbed = m x s x
or, 2717 J = 31.29 g x s x 139.6 oC
or, s = 0.6220 J/g.oC
Hence, the specific heat of the substance = 0.6220 J/g.oC
A 31.29 g sample of a substance is initially at 21.8 °C. After absorbing 2717 J...
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