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only do question f!!!!!! please be specific with step by step to use minitab to graphing 1. )The accompanying table gives the dry weights (Y) of 11 chick embryos ranging in age from 6 to 16 days (X). Also given in the table are the values of the common loga- rithms of the weights (Z). Age (X) (days) Dry Weight (M Logio Dry Weight (Z) 1.538-1.284 Age (X) (days) Dry Weight( 10 0.181 .03-0.742 -0.583 7 0.029 0.052 0.079 0.125 0.261 一1.102 12 13 14 15 16 0.425 0.738 1.130 1.882 2.812d. Sketch each estimated line on the appropriate scatter diagram. Which of the two regression lines has the better fit? Based on your answers to parts (a)-(c), is it more appropriate to run a linear regression of Yon Xor of Z on X? Explain. For the regression that you chose as being more appropriate in part (d), find 95% confidence intervals for the true slope and intercept. Interpret each interval with regard to the null hypothesis that the true parameter is 0. f. For the regression that you chose as being more appropriate in part (d), find and sketch 95% confidence and prediction bands. Using your sketch, find and interpret an approximate 95% confidence interval for the mean response of an 8-day-old chick

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The estimated regression line for Y on X is Versus Fits (response is Dry Weight[]) 1.00 0.75 0.50- 0.25 0.00 0.25 0.50 0.5 FiThe estimated regression fit line for Y on X is Versus Fits (response is Log of Dry Weights[Z]) 0.04 0.03 0.02 0.01 0.00 G0.0Calculate the 95% confidence interval for the true slope and intercept in more appropriate linear regression is Z on X. Where Parameter estimates of X 0.02807 3.316625.10 0.02807 3.3167 x3.1623 0.02807 10.48809 0.002676 S0.002676. (1) -0.19589+ where β value get from the SAS output, n 11 and α:05 By substituting the value (1) for S and use the t-table for to.s), the confidence interval for the true slope is (9-975)0. I 9589 ± 2.262 × 0.002676 = 0.1 9589 ± 0.006053 (0.20194,0.18984) The formula for the confidence interval for the y-intercBy substituting the value (2) for and use the t-table for (9,093) t for the P, s -2.68925+2.262x 0.030632-2.68925 0.069291 (9The null and alternative hypotheses are From the above output of Z on X to get βο p value 0.000 Use a significance level of α = 0.05 By the condition if P-value > , then do not reject the null hypothesis Ho Here the P- value is 0 < 0.05 Hence, the null hypotheses Howill be rejected Thus the B, values also should be given valid information to the model.To sketch the 95% confidence and prediction bands for more appropriate linear regression is Z on X The formula for Confidence bands: .S By using the given SAS output to get the value of confidence bands 95% Confidence Bands 1 .5497 1.4781 1.3489 1.2871 1.1485 1.09570.9489 0.9036 0.7504 0.7103 0.5536 0.5153 0.3586 0.3185 0.1653 0.1200 0.0268 0.0796 0.2182 0.2800 0. 4092 0.4808 The formula for Prediction bands:n (n-1)SBy using the given SAS output to get the value of confidence bands 95% prediction Bands 1.5868 1.4410 1.3886 1.2474 1.1909 1,0534 0.9937 0.8588 0.7970 0.6637 0.6008 0.4681 -0.4052 0.27200.2101 0.0752 0.0156 0.1220 0.1785 0.3197 0.3721 0.5179 Diagram for Confidence and Prediction bands:1.000 0.500 0449 0.000 9 10 14 15 16 0.132 0.372 0.500 log of Dry Weight 0583 -95% Confidence Bands -95% prediction Bands 0.742 0.903 1.000 1.102 1284 1.500 1.538 2.000 Age X)The approximate 95% confidence interval on the mean response for an 8-day-old chick is (1.149,-1.096) by using the confidence band formula where X, -8 1.000 0.500 0,000 10 14 15 16 0132 0.372 -+-log of Dry Weight 0.5 0.500 05153 0.583 -95% prediction Bands -95% Confidence Bands 87493 9036 1.000 -1 1.102 284 1.48 1.500 1.5 1.538 2.000 -2 Age (X) Hence the diagram shows that the lower limit of an 8-day-old chick is -1.149 and the upper limit of an 8-day-old chick is -1.096. Thus the dry weight of an 8-day-old chick is having within the

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