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chemist measures [H,O*] and TOH] in an aque- 11. A young ous solution at 25°C. He reports that [H2O*] = 1 x 108 and [OH] = 1x
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Answer #1

- The ionization of water can be given as - 2H20 (1) - HBO (aq) + OH (ar) ionization constant of water can be given as - ki -[H3O+ [OH-] = 10-14 Now, here at 25°c the measured that, – chemist [H3O+] = 1 x 10-8 aw (04-) = 1 x 10-8 Thus, – [H3O+] [ ostFor the other answers please post them as another questions......

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