Question

Calculate the molarity of the acetic acid solution using the equivalence point determined from the graph. The volume of the o
0.00840M
A2pH/AmL2 J.4 Second Derivative of Titration Curve 10 8 6 15,50 15.55 15.60 15.65 15.70 15.75 15.80 15.85 15.90 15.95 16.00 -

the molarity of the titrant was 0.09840 and the pH changes at around 15.85
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Giren Titrand = Acetic acid Polume of original solution = 25 mL Molarity of titraut = 0.09840 Volume of tilrout at equivalencsolution Using equation MV = M₂ V₂ (for Acetic acid) (for titraut) M, x 25 ml = 0.09840 M X 15.85 ml M 15.85 ) M =/0.09840 X

Add a comment
Know the answer?
Add Answer to:
the molarity of the titrant was 0.09840 and the pH changes at around 15.85 Calculate the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Since you know the molarity of the NaOH titrant and the volume added to the equivalence...

    Since you know the molarity of the NaOH titrant and the volume added to the equivalence point, as well as the volume of acid used (10.00 mL) and the mole:mole ratio of acid and base, determine the molarity of the known and unknown acids. (You did this calculation in a 1211L, General Chemistry I, experiment.) molarHy of NoOH-O.118 Volume odd volume used - 10 Ratio Acetic Acid Molarity 27.1 (2 pts.) Unknown Acid Molarity (2 pts.) Show calculations for the...

  • Exp 9 titration of vinegar procedure b molarity of NaOH = .0859 ROCEDURE B. DETERMINATION OF...

    Exp 9 titration of vinegar procedure b molarity of NaOH = .0859 ROCEDURE B. DETERMINATION OF CONCENTRATION OF ACETIC ACID IN UNKNOWN SAMPLES Titration of vinegar solutions Trial 1 Trial 2 Trial 3 1. Volume of vinegar solution being titrated in milliliters (mL) 25.00 mL 25.00 mL 25.00 ml 2. Volume of vinegar solution being titrated in Liters (L) 0.0250 L 0.0250 L 0.0250 L 3. Final buret reading in ml 16. 20m 16.316L 16.25ml 4. Initial buret reading in...

  • A vinegar titration was completed using a pH meter as an indicator of the changing pH....

    A vinegar titration was completed using a pH meter as an indicator of the changing pH. A 25.00 mL sample of diluted vinegar (diluted by a factor of 5) was placed in a beaker and subsequently titrated with 0.1098 M NaOH. A derivative curve of the titration suggested that the equivalence point occurred at 40.90 mL. Calculate the mass percent of CH_3COOH. (The density of vinegar is 1.008 g/mL.) Moles of base at the equivalence point = Moles of acid...

  • please help with my pre lab additional information Pre-Lab Questions: 1. What is the definition of...

    please help with my pre lab additional information Pre-Lab Questions: 1. What is the definition of an 'equivalence point' in an acid/base titration? (1 point) 2. In part one of the experiment, you will prepare the acid solutions being titrated from a stock solution. Describe how you will accurately prepare 10.00 mL of 0.100 M HCl solution using a 1.00 M HCI stock solution. In your response to this question, be very specific about the quantities of stock solution and...

  • 3. If 15.0 mL of 0.125 M phosphoric acid is titrated with 0.100 M NaOH, what...

    3. If 15.0 mL of 0.125 M phosphoric acid is titrated with 0.100 M NaOH, what volume of the titrant (in mL) must be added to completely neutralize the acid? Show all of your work (including the chemical equation). (1 point) Post-lab Questions: Experiment #9: Acid-Base Titrations Student Learning Objectives : Students will gain practice with the accurate preparation of solutions. Students will perform acid-base titrations and prepare titration curves. Students will identify strong and weak acids by the shapes...

  • 5. Determine the average value for the molarity of the acetic acid in vinegar. Show your...

    5. Determine the average value for the molarity of the acetic acid in vinegar. Show your calculation 6. Determine the deviation between each individual molarity for acetic acid and the average value from question 4, above. Notice that the formula below uses absolute values: you only care about how big the difference is not whether cach trial value was higher or lower than the average. Deviation = (individual trial value)-(average value from #5) Trial Ideviation Trial 2 deviation Trial 3...

  • How do I calculate the ionization constant for acetic acid from the measured pH of the acedic aci...

    How do I calculate the ionization constant for acetic acid from the measured pH of the acedic acid samples? Data and Calculations 1. Measurement of pH and fitration of acetfic acid solution Concentration of standardized NaOH titrant Mass concentration of acetic acid-aao Trial 3 Trial 2 Trial 1 Measured pht of the acetic acid solution Mass of acetic acid solution taken for titration. Initial buret reading of NaOH titrant Final buret reading of NaOH titrant Net volume of NaOH Millimoles...

  • 1. What is the definition of an 'equivalence point' in an acid/base titration? (1 point) 2....

    1. What is the definition of an 'equivalence point' in an acid/base titration? (1 point) 2. In part one of the experiment, you will prepare the acid solutions being titrated from a stock solution. Describe how you will accurately prepare 10.00 mL of 0.100 M HCl solution using a 1.00 M HCl stock solution. In your response to this question, be very specific about the quantities of stock solution and deionized water to be used in the dilution and the...

  • U Experiment 17B: Acid-Base Titration Report Data Table Trial 1 Trial 2 T Trial 3 Volume...

    U Experiment 17B: Acid-Base Titration Report Data Table Trial 1 Trial 2 T Trial 3 Volume of Acetic Acid Final buret reading 42.35 27.67 Initial buret reading 30.00 38.32 5.81 32.51 30.00 44.40 3.95 40.45 Volume of NaOH 27.67 Exact Molarity of NaOH (From 17A or see label) 1252 Calculations: 1. Calculate the molarity of the acetic acid for each trial and the average molarity Trial 1: Trial 2: Trial 3: Average Molarity of Acetic Acid = 2. Use the...

  • The titrant solution is on the last page. All the info needed is on the pages provided. paticularly on t...

    The titrant solution is on the last page. All the info needed is on the pages provided. paticularly on the last page Table 1: Standardization Data Trial 3 Trial 1 Trial 2 O.47644 0.4701 25. mL ou779 12.7mL 25. mL 12.4 mL Mass of KHP Initial burette reading 2.7mL 37,Sm 2.4m Final burette reading 12.7mL Volume of base used Data Analysis: 1. Write a balanced molecular equation (with phases, of course) for the reaction between the KHP and the titrant...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT