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- Part A If you want to drain a 560mL shake in 3.0 minutes, what pressure difference is needed? You can ignore the height dif
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Answer #1

Discharge, Q = V/t

Q = 560 x 10^-6/(3 x 60) = 3.11 x 10^-6 m^3/sec

dP = 8Q n L/pi r^4

dP = (8 x 3.11 x 10^-6 x 0.6 x 0.22)/(pi x (0.28 x 10^-2)^4)

dP = 1.70 x 10^4 Pa

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