SOURCE OF VARIATION | S.S | D.F | M.S | F CAL | P VALUE |
TREATMENTS | 1000 | 4-1=3.00 | 333.33 | 11.67 | 0.0001 |
BLOCKS | 400 | 8-1=7.00 | 57.14 | ||
ERROR | 600 | 21.00 | 28.57 | ||
TOTAL | 2000 | 31.00 |
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of...
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary and p-value to 4 decimals). If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 1,100 Blocks 600 Error Total 2,300 Use = .05 to test for any significant differences.
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals, if necessary and p-value to 4 decimals). If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F D -value Treatments 900 Blocks 300 Error Total 1,600 Use a - .05 to test for any significant differences. The p-value is Select What is your conclusion? Select Check My Work (4 remaining)
An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). If answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 800 Blocks 500 Error 600 Total 1900
An experiment has been conducted for four treatments with eight blods. Complete the following analysis of variance table (to 2 decimals but p-value to decimals, if necessary). If answer is zero enter"0" Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Blocks 500 Error 1.000 Us 05 to test for any cantofferences The values Select your new What is your condition? Check My Work
A n Score: 0.00% Save Submit Assignment for Grading estions Exercise 13.23 Algorithmic Question 8 of 14 Check My Work eBook An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). If answer is zero enter "0" Source of Variation Sum of Squares Degrees of Freedom Mean Square p-value Treatments 900 Blocks 400 Error Total 1,600 Use a - .05 to test...
A randomized block design is used in an experiment. There are 4 treatments and 3 blocks. Use the information below to complete the table. Ź(2) - x)?= 50 (<1– )² = 712 Σα, (Xi - x)2 = 98 j=1 i=1 j=1 Degrees of Freedom Sum of Squares Mean Square f P value Source of Variation Treatments Blocks Error Total
Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table. Treatment 10 2 12 3 18 420 Blocks 16 19 15 19 Use α .05 to test for any significant differences. Show entries to 2 decimals, if necessary. Round p-value to four decimal places. If your answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square Treatments p-value 43 85.7723.39 0.0000 343.07...
The following data are from a completely randomized design. In the following calculations, use a = 0.05. Treatment Treatment Treatment 88 77 ł / 51 58 132.67 113.33 54.00 a. Use analysis of variance to test for a significant difference among the means of the three treatments. Source of Variation Sum of Squares Degrees Mean Square p-value (to whole number of (to whole number) bers (to 2 decimals) to - decimals (to 3 decimals) Freedom Treatments Error Total The p-value...
An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic 49 42 Car Compact Intermediate Full-sized 54 44 59 46 Use a = .05 to test for any...
The following data were obtained for a randomized block design involving five treatments and three blocks: SST = 490, SSTR = 310, SSBL = 95. Set up the ANOVA table. (Round your value for F to two decimal places, and your p-value to three decimal places.) Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments Blocks Error Total Test for any significant differences. Use α = 0.05. State the null and alternative hypotheses. H0: At...