Question

Table 20.2 Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr (s) -0.74 Fe2+ (aq) + 2e- Fe () -0.440 Fe3+ (aq) + e- → Fe2+ (s) +0.771
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Answer #1

Ans is C +1.51V

Cr(S) + 3Fe3+(aq)\rightarrow 3Fe2+(aq) +Cr3+(aq)

Standard cell potential(Eocell): The cell potential when concentration of electrolytes in two half cells are unity( Molarity is 1M) is called standard cell potential.

Here

Reaction at anode is

Cr(s)\rightarrow Cr3+(aq)

EoCr3+/Cr = -0.74V(Given in data)

Reaction at cathode

Fe3+\rightarrow Fe2+

EoFe3+/Fe2+ =+0.771V

Eocell = Eocathode - Eoanode

=0.771V-(-0.74)V =1.511V

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