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A mixture of He, N,, and Ar has a pressure of 24.2 atm at 28.0 °C. If the partial pressure of He is 2325 torr and that of Ar

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Answer #1

From the given data,

Total pressure of mixture = 24.2 atm.

The partial pressure of He= 2325 torr

= (2325 torr)×(1atm)/(760torr)

= 3.059 atm

The partial pressure of Ar = 1351 mm Hg

= (1351 mm Hg)×(1atm)/(760 mm Hg)

= 1.7776 atm.

Hence, from Dalton's law of partial pressures,

Total pressure = sum of all partial pressures

24.2 atm = 3.059 atm + 1.7776 atm + pressure of N2

Hence,

Partial pressure of N2 = 19.36 atm

Partial pressure of N2 = 19.36 atm = 19.4 atm.

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