Molarity of Ba(OH)2=moles/lit.
=0.06000/0.7000
=0.08571M
Eqution:
Ba(OH)2 +H2O----->Ba^+2 + 2 OH-
0.0857M 2*0.0857=0.1714M of Hydroxide
We know that,
pOH= - log10[oh-]
=-log10[0.1714]
=-(-0.7659)
pOH =0.7659
We know that,
pH+pOH=14
pH+ 0.7659=14
PH=14-0.7659
pH=13.23
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