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Consider an economy such that Output per worker: yt = 2k0.5 Capital per worker: kt Depreciation rate: 8 = 0.4 Saving rate: s

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Solution:

Q1. In the steady state, as already mentioned in the question that the capital per worker does not change. Thus, kt+1 = kt = k*

So, kt+1 - kt = 0

s*yt - d*kt = 0, where d is delta for depreciation rate

Using yt = 2*kt0.5, we have s*(2*kt0.5) = d*kt

We can write this as 2sk*0.5 = dk* (as kt (= kt+1) = k* in steady state)

Substituting for s and d, 2*0.2*k*0.5 = 0.4*k*

k*/k*0.5 = 0.4/0.4

k*0.5 = 1 or k* = 1

Thus, correct option is (d) 1.

Q2. In general terms, we can find the steady state level of capital per worker as:

k*/k*0.5 = 2s/d

So, k*0.5 = 2s/d

Or k* = (2s/d)2 = 4s2/d2

Now, if saving rate doubles, k* = 4*(2s)2/d2 = 4*(4s2/d2) so, capital per worker increases by more than double, it becomes 4 times (it quadruples).

Similarly, if depreciation rate decreases by 50%, so new depreciation rate is 0.5d, then

k* = (4s2/(0.5d)2) = 4*(4s2/d2) which is again 4 times (not 2 times)

So, correct option is (d) none of the above.

Q3. We already know that in steady state, capital per worker does not change. Since, yt = 2*kt0.5, that is output per worker depends entirely on capital worker, if capital per worker is unchanged, even output per worker is unchanged.

Further, capital per worker = capital/number of workers, so if number of workers does not change (and capital per worker anyway does not change), capital will also not change in steady state.

With unchanged capital and unchanged number of workers, output will clearly be unchanged, as it depends on these two factors only.

Thus, correct option is (d) All of the above.

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