The temperature of an aluminum disk is increased by 220 ∘C. By what percentage does its volume increase?
Solution)
Given
ΔT = 220 C
We know, β of alluminium = 69*10^-6
Now,
Change in volume ΔV/V = β * ΔT = 69*10^-6 * 220
ΔV/V = 0.01518
% of volume increase = ΔV/V * 100 = 1.518 % (Ans)
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