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Label the spectra and propose a structure for the compound.

Compound 3 IR Spectrum quid 4000 3000 2000 V (cm 1000 ) 1200 800 of base peak more Cg H100 280 40 80 120 160 200 240 C NMR Sp
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Answer #1

DBE = 9 + 1 -10/2 = 5

Solution 1723 cm-1 => Aldehydic C=0 stretching 1H NMR sprotib au CHOO (a) tave aromatic foreton comes at = 7.1-7.3 ppm (mal

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