would you show me the step by step to solve this problem, thank you so much
Ka = 1.8*10^-5
pKa = - log (Ka)
= - log(1.8*10^-5)
= 4.745
use formula for buffer
pH = pKa + log ([CH3CO2Na]/[CH3CO2H])
5.0 = 4.7447 + log ([CH3CO2Na]/[CH3CO2H])
log ([CH3CO2Na]/[CH3CO2H]) = 0.2553
[CH3CO2Na]/0.2 = 1.8
[CH3CO2Na] = 0.36
volume , V = 5*10^2 mL
= 0.5 L
use:
number of mol,
n = Molarity * Volume
= 0.36*0.5
= 0.18 mol
Molar mass of CH3CO2Na = 82 g/mol
use:
mass of CH3CO2Na,
m = number of mol * molar mass
= 0.18 mol * 82 g/mol
= 14.8 g
Answer: c
would you show me the step by step to solve this problem, thank you so much...
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