Question

(15502.19.2) 7. A single pulse of a laser yields an average of 5.00 x 1018 photons with = 532 nm. If melting ice to water at 0°C requires 6.01 kJ/mol, what is the fewest number of laser pulses needed to melt 125.3 g of ice? 532, Ech

Answer 1

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Molar mass of water lice) = 18g1 mol is moles of ice = 125.3 mol Total energy required to melt ice = 6.01 kJ/mol x 125.3 mol 18 4108363 KJ Energy of single laser pulse = no of photon x Energy of one photon = 5:00 % 1018 x hc = 5.00 8 10 18 X 6.64*10-34 x 3 x 108 532 X10-9 - 10872 J a. No of laser Pulse = Total Energy Energy of one pulse 4108363x 1037 10872 J 22 348.4 o fewest No of pulse required 22349 = 122349 Ans