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A 20.0kg box is suspended by a very light rope wrapped around a solid disc of...

A 20.0kg box is suspended by a very light rope wrapped around a solid disc of 0.5m in diameter. The mass of the disc is 10kg. The disc pivots on a frictionless axle through its center. The box is then released from rest and falls 15m to the floor. Moment of inertia of a solid disc I=1/2_MR^2.
a) Draw free body diagram for the box and the disc.
b) Determine the tension in the rope while the box is falling.
c) Determine the acceleration of the box while the box is falling
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Answer #1

Tz m (9-a)= 20x(9.8-a) Tx R = I 2 Tx0.25 = 10x0.25 x a pas T=5a T= 20 (987) T= 39.2 N. ® a = 39,90 = 1.84 m/s2

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