Question

please show all steps determining final answer (handwritten please). Please explain how to solve for X1 X2

For this week's physics lab, the experimental setup consists of two gliders on a horizontal frictionless air track (see figure below). Each glider supports a strong magnet centered on top of it, and the magnets are oriented so they attract each other. The mass of glider 1 and its magnet is 0.090 kg, and the mass of glider 2 and its magnet is 0.204 kg. You and your lab partners are instructed to take the origin to be at the left end of the track and to center glider 1 at x1 = 0.105 m and glider 2 at x2 = 1.680 m. Glider 1 is 9.1 cm long, and glider 2 is 19.6 cm long, and each glider has its center of mass at its geometric center. When the two gliders are released from rest, they will move toward each other and stick. 1 NS NS2 (a) Predict the position of the center of each glider when they first touch. (Enter your answers from smallest to largest.) X2 =

Answer 1

9.lem 19.6 cm 2 0.090 kg 0.209kg 0.105 m 11 680 m The center of mass of two glider will be at a. Emixi (0.090 80 105) & (0.2048 1.680) {mi 0.204 + 0.090 = 1.198 von 9.1 cm 1966 If they joined together, their center of masses are at distance of reta) = (9.1 & 19.6 cm a 14.35cm Their center of mans will be at o as there in no externalago e force acting on the mystem. i mah & men 0.204 - Po 2-13 , 01204 -0.090, 0.114.19 mtu2 0204 +0.090 0.29 mq- x2 = A 14.35 - 5.564. 4 = 9.957 cm., uze 4.393 cm Hence, after collision, the geometri center of 1 1 = 1.198 m-0.09957m 21.0984 m and the distance for. 2. 1. 198+ 0.09957 = 1.2976 m