Question

6. Write the full ground state electronic configuration for each of the following. a. Rb b. S2 ntooga sidi a c. Co2 d. Sn

Answer 1

6. Electronic configuration in a way of dencribing the number of electronoin an atom of an elements by of finding It given unaful information about the tendency of Dumber of an electron near to the nucleus about the n valence electrono in an atom, the last shell occupied by an electron etc. (a) Rubidium (R6) in an element with atomic number 37. This indicaten that Rb contain 37 eletrona. of in a s' block element and the last electron enterra the s' orbital. The electronic configuration of Rb in 15² 25² 2p 35² 3p 3d 4² 496 55' o with (6) Sulfur (s) in an element of atomic number 16. Soga. neutral sulfur atom has a total of 16 electrona surrounding ito nucleus. The electronic configuration of of neutral sulfur atom will be 15² 25² 2p% 35² 3 pq. Now, the sulfide anion, s2- in formed when this electrons are added to a neutral ouffer atom. These two electrona will be added to the 3 orbital which can hold a maximum of sine electrono. so the electronic configuration of sulfide anion (52) will be 15²2s²2p8 35² 3 po sation ic Cobalt (Co) in an element of atomic number . Co atom contain 27 electrons. The electronic contin of Co in 15²25² 28 35² 388 46² 3d7. when co losen 2 elections to become co2t It lonen the electrons which are in 45² nothin and because the electrono in 45² have high reactivity. so, the electronic configuration of co 2 in 15 25 28 35 36 37

(d) Tin (Sn) in an element of atomic number 50. It indicates that sn atom hon 50 electronn. The electronic configuration of Sn atom in 15² 25² 2p% 35² 3p 45² 3 do 4 p 84 d'° 55² 5020 A nign of +4 on tin atom indicated that in atom has loot 4 electronn. So, the electronic configuration of snft will be 15² 25² 2P6 35² 386 3810 45² 4dlo.