Question

1. According to the following reaction, how many grams of AICI; will be formed if the reaction was started with 123.2 g of Cl2 and excess Al? 2 Al + 3 Cl2 → 2 AICI: 2. From the prior question, if 126.8 g AlCl3 is actually recovered, what is the percent yield?
Part 2

Answer 1

1. 2A6 + 3Cl2 - 2 Alchz mass of cha = 123.2 g Molar mass of ch = 70.906 g/mol Moles = Mass moean mass Moles = 123.2 = 1.737 mole 70.906 3 moles of cl 2 moles allez 010737 moles of lag mous of alle = 2 x 01 737 = 1.1583 nioles mass of Alllz formed = moles x . molar mass = 1.1583 X 133034 mass of Alcla formed = 154.447g| % yield = actual yield . Theoretical yeel 126.8 x 100 154.447 2 — x loo % yield = 82.1 %