Question

LEARN MORE REMARKS Calculating actual flow rates of real fluids through plpes is in fact much more complex than presented here, due to viscosity, the possibility of turbulence, and other factors. QUESTION Find a symbolic expression for the limit of speed v, as the lower cross sectional area A, opening becomes negligibly small compared to cross section Az. (Use the following as necessary: 8, 9, Aj, and Az.) What is this result called? Reynolds Number Torricelli's Law O Stokes's Law O Archimedes' Principle Bernoulli's Equation PRACTICE IT Use the worked example above to help you solve this problem. A large pipe with a cross-sectional area of 1.25 m² descends 5.05.m and narrows to 0.500 m2, where it terminates in a valve at point (see figure). If the pressure at point is atmospheric pressure, and the valve is opened wide and water allowed to flow freely, find the speed of the water leaving the pipe. m/s EXERCISE HINTS: GETTING STARTED I I'M STUCK! Water flowing in a horizontal pipe is at a pressure of 1.45 x 10 Pa at a point where its cross-sectional area is 2.00 m2. When the pipe narrows to 0.400 m2, the pressure drops to 1.16 x 105 Pa. (a) Find the water's speed in the wider pipe. m/s (b) Find the water's speed in the narrower pipe. m/s Need Help? Read It Talk to Tutor MacBook Air

Answer 1

According to Bernouli's theorem, . At point å and B?.. Par@gh + 2 puz? = PB+ Pg 62 tk PV2 M, B our pgn = 1/2 PLY, ?-1122) : Pa = 1B are atmospherie 29h = vie (in weite). O Friom continuity equation; AM = A212 pressure. . Vz - As from 20 vite /29 h = V² (1-4/2) 29h Evi" (la) since A2 >>A VASO li 2gh = 1,2 lv i = 12gb of this result is called Bernouli's equation-