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Check Answer Question 10 of 10 The table contains the volume of reagents combined in a series of trials for the reaction Fe(N
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Answer #1

TRIAL 1

[Fe+3] = Initial concentration of Fe(NO3)3 * Volume of the Fe(NO3)3 solution/ Total volume = 0.0020 M * 5 / 10 = 0.001 (M)

[SCN-] = Initial concentration of KSCN * Volume of the KSCN solution/ Total volume = 0.0020 M * 2/ 10 = 0.0004 (M)

TRIAL 2

[Fe+3] = 0.0020 M * 5 / 10 = 0.001 (M)

[SCN-] = 0.0020 M *3 / 10 = 0.0006 (M)

TRIAL 3

[Fe+3] = 0.0020 M * 5 / 10 = 0.001 (M)

[SCN-] = 0.0020 M *4 / 10 = 0.0008 (M)

TRIAL 4

[Fe+3] = 0.20 M * 9 / 10 = 0.18 (M)

SCN-] = 0.0020 M *1 / 10 = 0.0002 (M)

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