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8. P(sum=10|sum>6) = ?
So,
Sum is 7 in {3,4},{4,3},{5,2},{2,5},{6,1},{1,6} = 6 cases
Sum is 8 in {4,4},{5,3},{3,5},{2,6},{6,2} = 5 cases
Sum is 9 in {4,5},{5,4},{3,6},{6,3} = 4 cases
Sum is 10 in {4,6},{6,4},{5,5} = 3 cases
Sum is 11 in {6,5},{5,6} = 2 cases
Sum is 12 in {6,6} = 1 cases
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so sum>6 is 6+5+4+3+2+1 = 21
So, out of these 21 cases, 3 cases have sum equal to 10.
Hence, P(sum=10|sum>6) = sum is greater than 6 and is 10 / total
cases where sum >6
= 3/21
= 1/7
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