Ans 6(4)
The balanced reaction
E-stilbene + Bromine = meso-stilbene dibromide
C14H12 + Br2 = C14H12Br2
Mass of E-stilbene = 0.90 g
Molecular weight of E-stilbene = 180.24 g/mol
Moles of E-stilbene = mass/molecular weight
= (0.90 g) / (180.24 g/mol)
= 0.004993 mol
From the stoichiometry of the reaction
1 mol E-stilbene produces = 1 mol meso-stilbene dibromide
Moles of meso-stilbene dibromide = 0.004993 mol
Theoretical yield of meso-stilbene dibromide
= moles x molecular weight
= 0.004993 mol x 340.05 g/mol
= 1.697 g
meso-stilbene dibromide when 0.90 g of E-stilbene are reacted 6.(4) Calculate the theoretical yield of meso-stilbene...
please help with number 6! 1.(2) What is the meaning of “E” in E-stilbene? 2.(4) What functional groups are present in E-stilbene? 3.(2) Write the reaction that occurs between E-stilbene and bromine. 4.(4) Write the mechanism for the addition of bromine to €- stilbene to give meso-stilbene dibromide via the intermediate cyclic bromonium ion. 5.(2) Which reagent, E-sitlbene or bromine, acts as the nucleophile in this reaction? Which reagent is the electrophile? 6.(4) Calculate the theoretical yield of meso-stilbene dibromide...
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