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need help with these please
4. With what volume of 5.00 MHF will 4.72 g of calcium hydroxide react comp the following reaction? 2HF + Ca(OH), CaF, +2H,0
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4) Equation: Ca(OH), (aq) + 2HF(aq) — Caf, (aq) + 2H,0(1) 1 mol Ca(OH) No of moles of Ca (OH), = 4.72 g 24.093 = 0.0637 mol C

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