Question

3cer's law states that the absorbance of a solution is directly proportional to the molar Concentration of a solution. If you plot absorbance versus molar concentration (molarity), the esulting graph yields a straight line. The equation for the straight line can be used to determine he concentration of an unknown solution from a measurement of its absorbance. You need to prepare 10.0 mL of diluted Cuso, solutions with the concentrations listed for Trials 1 through 4 in the table below. Before coming to lab, determine what volumes of 0.040 M CuSO, stock solution and H.O need to be mixed together. Fill in the table with the volumes you determined. Trial Number 0.040 M Cuso. (mL) H0 (mL) Diluted Concentration (M) 0.0050 0.010 0.020 0.030 0.040 stock solution 0 Transfer -35 ml of 0.040 M Cuso, solution to a clean and dry 100 mL beaker, Label clean dry. 15 x 150 mm test tubes 1-4 (the fifth solution is the undiluted stock

Please show calculations for all 4 trials

Answer 1

Calculation 1) C1V1 = C2V2

final volume ( V2 ) = C1 V1 / C2 = ( 0.04 M ) x ( 35 mL ) / 0.0050 M = 280 mL CuSO4

volume of H2O = 280 - 35 = 245 mL

2 ) V2 = ( 0.04 M ) x ( 35 mL ) / ( 0.01 M ) = 140 mL CuSO4

volume of water = 140 - 35 = 105 mL

3) V2 = ( 0.04 M ) x ( 35 mL ) / ( 0.02 M ) = 70 mL CuSO4

volume of H2O = 70 - 35 = 35 mL

4) V2 = ( 0.04 M ) x ( 35 mL ) / 0.03 M = 46.66 mL

volume of water = 46.66 - 35 = 11.66 mL