Which electrode will be positive? : left
What voltage will the voltmeter show? : 0.062 V
Explanation
Left half cell : Anode reaction : M (s) M3+ (aq) + 3 e-
Right half cell : Cathode reaction : M3+ (aq) + 3 e- M (s)
According to Nernst equation,
Ecell = -[(R) * (T)] / [(n) * (F)] * ln([M3+]anode / [M3+]cathode)
where R = constant = 8.314 J/mol-K
T = temperature = 40.0 oC = (273 + 40) = 313 K
n = number of electrons transferred = 3
F = Faraday's constant = 96485 C/mol
Substituting the values,
Ecell = -[(8.314 J/mol-K) * (313 K)] / [(3) * (96485 C/mol)] * ln[(2.50 x 10-3 M) / (2.50 M)]
Ecell = 0.062 V
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