Question

9. A ray of violet light is exactly horizontal after entering a 45-45-90° glass prism from air, as shown: a. Sketch the incident violet ray to the left of the prism. b. Sketch the rest of the violet ray through the glass and well beyond the right side of the prism. 90.0 o 45.0 n glass 45.0 Nair c. If n glass = 1.35 for violet light, show that the incident angle 0, for the entering ray must be 72.7°: Suppose that a ray of red light were to strike the left side of the prism at the same incident angle as the violet light (72.7°). d. If nred <nviolet in the glass (true for most substances), sketch the complete path of the red light ray entirely through the glass and into the air on the right side of the prism. (Note: After entering the glass, the red ray will NO LONGER overlap the violet ray!) Qualitatively, in what ways does the red ray's path differ from the violet ray's path? e. If n glass = 1.32 for red light, calculate the final angle of refraction for the red ray as it leaves the glass on the right side of the prism: A. 49.2°D. 65.7° B. 53.9°E. 71.9° C. 58.1°

Answer 1

Soluton snell 's Law Aprly ing ni Sini n2 sihr sIx Sin: t35 A Siyg Sin (6.g549) 45 2.70 Sin (o.9549) = 72-7° Sinie FoY Second medium as angle of Incsdence 's 45 So agaun Q2 72-7° colour red For ni Sin 72.7° x Sin 72-7°2 A. (-3 2 xSinr Sin72-7 72.7 46 32* I32 46.32 angle of Ircidence For Sccond Surfaie O 90-46.32 = 43.68 32 x Siny3.68" 1x Sihr r6 5-7