Question

(3) Explain whether the percent error suggests that too little HCL or too much HCL was...

(3) Explain whether the percent error suggests that too little HCL or too much HCL was added in your titrations.

experimental molarity of NaOH - 0.300 mol/L

actual molarity - 0.430 mol/L

((0.300 - 0.430)/0.430) x 100

percent error = -30.233%

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Answer #1

3) From the given data,

actual molarity = 0.430M

Experimental molarity = 0.300M

Hence, it is clear that experimental molarity is very less when compared to actual molarity.

Also we know that,  

HCl + NaOH ----------> NaCl + H2O

From the equation,both the number of moles of HCl and NaOH are in same proportion.

So from experimental value of NaOH, it is clear that Too little HCl is added in the titration.

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