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11. Calculate the pH and pOH of a solution that is 0.075 M HCN and 0.06 M NaCN.

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Answer #1

[HC] = 0.075 [MacN] = 0.06 [en-)= 0.06 The reaction is HENTH2O = H₂ottan kas [Hz ot] [en] [HN] the ka of Hen is 4.9x10-10 =>6:46 - pod) 64h - 12.b -hi = had a Hd_h1 = Hed Tizb = 4: reb = Hd felz.b -) -= d <= (6_98521.9) bop End 42

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