(a.) gas phase enthalpy change = 42 kJ/mol
(b.) Is the reaction exothermic or endothermic? : endothermic
(c.) Is the reaction likely to proceed spontaneously in the direction written? : No
Explanation
For the given reaction,
gas phase enthalpy change = bond energy of reactants - bond energy of products
gas phase enthalpy change = (Ho benzene-H) - (Ho H-Cl)
gas phase enthalpy change = (473 kJ/mol) - (431 kJ/mol)
gas phase enthalpy change = 42 kJ/mol
Use the References to access important values if needed for this question. For the reaction below...
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