Question

A solid conducting sphere of radius 2.00 cm has a charge of 9.20 μC. A conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of-1.92 μC. Find the electric field at the following radii from the center of this charge configuration (a) r-1.00 cm magnitude 0 direction N/C The magnitude is zero. (b) r-3.00 cm magnitude 9.2e7 direction radially outward (c) r-4.50 cm magnitude 0 direction N/C The magnitude is zero. (d) r= 7.00 cm magnitude Determine the amount of charge enclosed by a spherical Gaussian surface through the point of interest and apply direction 0.353e7X Gausss law to determine the field at that location. N/C radially outward Need Help? Read ItMaster I

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Answer #1

D)

Electric field, E = k q/r^2

E = (9 x 10^9)(9.2 x 10^-6)/0.07^2 = 1.69 x 10^7 N/C

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