Question

uestions 3-6 concern the cadmium absorption line at 228.8 nm that arises from an 1So-S1 transition. What are the spin multiplicities of the ground and excited electronic states? nal answer: What are the statistical factors (P = 2J +1) for the excited (P)) and ground (Po) electronic states of Cd? al answer: Calculate the ratio of N/No for Cd (N; and No are the number of atoms in an excited state and the ground state, respectively) in an air-acetylene flame (2250 °C)? (h6.62608x 10-34 Js) al answer: What percent of the Cd atoms is in the excited state? al answer:

Answer 1

257T So 'Si Ground - Excited Team symbol sepresented by spin multiplicity - 25 +1 Spin multiplicity of Ground Lg and excited state © Pi - 25+ = (2x1 +1) = 3. Po - 2J+L = (2x0+1 = 1 Ni - eA/KT (5) Ne he 3 JKT. - 6-626 x103458 x3x108 mis e 228.8 x10-9m x 1.38 x 1023 Jktx 2523K. -24.95 Nj = 1.46*10-11 No. Percent of Cd in excited state: Ni x100 - 1-46 x 10" xloo. No = 1.46 x 109%